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# Python内置函数bin() oct()等实现进制转换 【轉】 发表于 2013-9-22 23:06:09 | 显示全部楼层 |阅读模式
http://www.jb51.net/article/32927.htm

bin(x)
Convert an integer number to a binary string. The result is a valid Python expression. If x is not a Python int object, it has to define an __index__() method that returns an integer.
oct(x)
Convert an integer number to an octal string. The result is a valid Python expression. If x is not a Python int object, it has to define an __index__() method that returns an integer.
int([number | string[, base]])
Convert a number or string to an integer. If no arguments are given, return 0. If a number is given, return number.__int__(). Conversion of floating point numbers to integers truncates towards zero. A string must be a base-radix integer literal optionally preceded by ‘+' or ‘-‘ (with no space in between) and optionally surrounded by whitespace. A base-n literal consists of the digits 0 to n-1, with ‘a' to ‘z' (or ‘A' to ‘Z') having values 10 to 35. The default base is 10. The allowed values are 0 and 2-36. Base-2, -8, and -16 literals can be optionally prefixed with 0b/0B, 0o/0O, or 0x/0X, as with integer literals in code. Base 0 means to interpret exactly as a code literal, so that the actual base is 2, 8, 10, or 16, and so that int('010', 0) is not legal, while int('010') is, as well as int('010', 8).
hex(x)
Convert an integer number to a hexadecimal string. The result is a valid Python expression. If x is not a Python int object, it has to define an __index__() method that returns an integer.
 ↓ 2进制 8进制 10进制 16进制 2进制 - bin(int(x, 8)) bin(int(x, 10)) bin(int(x, 16)) 8进制 oct(int(x, 2)) - oct(int(x, 10)) oct(int(x, 16)) 10进制 int(x, 2) int(x, 8) - int(x, 16) 16进制 hex(int(x, 2)) hex(int(x, 8)) hex(int(x, 10)) -

bin()、oct()、hex()的返回值均为字符串，且分别带有0b、0o、0x前缀。

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